Python Selenium find_elements_by_class_name Error

I am scraping a google page that has returned links to Linkedin profiles.

I want to collect the links on a page and put them in a python list.

Problem is I can't seem to properly extract them from the page and I don't know why.

Google source code looks like this:

The page displays 10 of the following:

Mary Smith - Director of Talent Acquisition ...
https://www.linkedin.com › marysmith
Anytown, Arizona 500+ connections ... Experienced Talent Acquisition Director, with a 
demonstrated history of working in the marketing and advertising ...

The source code looks like this:

<div data-hveid="CAIQAA" data-ved="2ahUKEwjLv6HMr4HmAhWluVkKHfjfA1EQFSgAMAF6BAgCEAA">
   <div class="rc"> 
       <div class="r">
           <a href="https://www.linkedin.com/in/marysmith" ping="/url?sa=t&amp;source=web&amp;rct=j&amp;url=https://www.linkedin.com/in/marysmith&amp;ved=2ahUKEwjLv6HMr4HmAhWluVkKHfjfA1EQFjABegQIAhAB">
               <h3 class="LC20lb"><span class="S3Uucc">Mary Smith - Director of Talent Acquisition, Culture Curator ...</span></h3><br>
               <div class="TbwUpd">
                   <cite class="iUh30 bc">https://www.linkedin.com › marysmith</cite>
              </div>
           </a>
           ...

In my script I'm using Selenium and find_element_by_class_name()to collect all the instances of the links to Linkedin. The one in the above example is https://www.linkedin.com › marysmith. It is one line of code where I use driver.find_element_by_class_name() with the particular class name:

linkedin_urls = driver.find_element_by_class_name("iUh30 bc")

However I get the following error:

selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"[name="iUh30 bc"]"}

I've tried various permutations and other classes but it won't work. If I use the X_Path for one of those links the script WILL return that single link.

What am I doing wrong?