In selenium, when I search Xpath how do I capture the element two positions before?

In Python 3 and selenium I have this script to automate the search of terms in a site with public information

from selenium import webdriver

# Driver Path
CHROME = '/usr/bin/google-chrome'
CHROMEDRIVER = '/home/abraji/Documentos/Code/chromedriver_linux64/chromedriver'
# Chosen browser options
chrome_options = webdriver.chrome.options.Options()
chrome_options.add_argument('--window-size=1920,1080')
chrome_options.binary_location = CHROME

# Website accessed
link = 'https://pjd.tjgo.jus.br/BuscaProcessoPublica?PaginaAtual=2&Passo=7'

# Search term
nome = "MARCONI FERREIRA PERILLO JUNIOR"

# Waiting time
wait = 60 

# Open browser
browser = webdriver.Chrome(CHROMEDRIVER, options = chrome_options)
# Implicit wait
browser.implicitly_wait(wait)
# Access the link
browser.get(link)

# Search by term
browser.find_element_by_xpath("//*[@id='NomeParte']").send_keys(nome)

browser.find_element_by_xpath("//*[@id='btnBuscarProcPublico']").click()

# Searches for the text of the last icon - the last page button
element = browser.find_element_by_xpath("//*[@id='divTabela']/div[2]/div[2]/div[4]/div[2]/ul/li[9]/a").text
element
'»'

This site when searching for terms paginates results and always shows as the last pagination button the "»" button.

The next to last button in the case will be "›"

So I need to capture the button text always twice before the last one. Here is this case the number "8", to automate page change - I will know how many clicks on next page will be needed

Please, when I search Xpath how do I capture the element two positions before?